Two events $A$ and $B$ are independent if:
A$P(A \cap B) = P(A)\cdot P(B)$ for both events here
B$P(A \cup B) = P(A) + P(B)$, the mutually exclusive case
C$P(A) = P(B)$ on the school chart at all the times always
D$A$ and $B$ are disjoint, which always makes them independent
Answer & Solution
Correct answer: A. $P(A \cap B) = P(A)\cdot P(B)$ for both events here
Independence: $P(A \cap B) = P(A)\cdot P(B)$.
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