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The middle term in $(x + y)^6$ is the term with index:
A$T_4$, equal to the third term in the expansion on the chart
B$T_2$, equal to the second term in the small expansion of $(x+y)^6$
C$T_5$, the term containing $x^2 y^4$ as a fraction in the chart here
D$T_4 = \binom{6}{3}x^3 y^3$, the single middle term of the expansion
Answer & Solution
Correct answer: D. $T_4 = \binom{6}{3}x^3 y^3$, the single middle term of the expansion
$n = 6$ is even, so single middle term is $T_{n/2+1} = T_4 = \binom{6}{3} x^3 y^3$.
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