Home › JEE Main › Mathematics › Binomial Theorem › The middle term in $(x + y)^6$ is the term with …
The middle term in $(x + y)^6$ is the term with index:
A$T_4$, equal to the third term in the expansion on the chart
B$T_2$, equal to the second term in the small expansion of $(x+y)^6$
C$T_5$, the term containing $x^2 y^4$ as a fraction in the chart here
D$T_4 = \binom{6}{3}x^3 y^3$, the single middle term of the expansion
Answer & Solution
Correct answer: D. $T_4 = \binom{6}{3}x^3 y^3$, the single middle term of the expansion
$n = 6$ is even, so single middle term is $T_{n/2+1} = T_4 = \binom{6}{3} x^3 y^3$.
Related questions
In the expansion of a bracket raised to four, the sum of indices is:How many terms are in the expansion of a bracket raised to twelve?How many terms are in the expansion of a bracket raised to five?In the last term of the expansion, the index of b is:In the first term of the expansion, the index of b is:In the first term of the expansion, the index of a is:The general rule for expansion is built using the concept of:Why is Pascal's triangle awkward for a large index?