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The sum of binomial coefficients $\binom{n}{0} + \binom{n}{1} + \cdots + \binom{n}{n}$ equals:
A$2^n$, by setting $a = b = 1$ in $(a + b)^n$ on chart
B$n!$, the factorial of $n$ from the largest term here
C$n^2$, the squared count of terms in expansion
D$2n$, twice the index of the expansion sum here
Answer & Solution
Correct answer: A. $2^n$, by setting $a = b = 1$ in $(a + b)^n$ on chart
$(1 + 1)^n = 2^n = \sum\binom{n}{k}$.
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