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The sum to $n$ terms of a GP with first term $a = 2$ and ratio $r = 3$ is:

A$2(3^n + 1)/2$, missing the $-1$ in the formula here
B$2\cdot 3^n$, ignoring the sum formula entirely
C$S_n = 2(3^n - 1)/(3 - 1) = 3^n - 1$, by the GP formula
D$2n\cdot 3^{n-1}$, the term-by-term sum on the worksheet
Answer & Solution
Correct answer: C. $S_n = 2(3^n - 1)/(3 - 1) = 3^n - 1$, by the GP formula
$S_n = a(r^n - 1)/(r - 1) = 2(3^n - 1)/2 = 3^n - 1$.
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