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The number of ways to choose $3$ players from a class of $10$ for a team (order does not matter) is:
A$1000$, the cube of the class size for selection
B$30$, simply 10 times 3 by linear scaling here
C$120$, since $^{10}C_3 = 10!/(3!\cdot 7!) = 120$
D$720$, mistakenly using $^{10}P_3$ instead of combination
Answer & Solution
Correct answer: C. $120$, since $^{10}C_3 = 10!/(3!\cdot 7!) = 120$
$^{10}C_3 = 10!/(3!\cdot 7!) = 120$.
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