The mass defect $\Delta m = 0.5$ u of a nucleus corresponds to a binding energy of approximately:
A$0.5$ MeV, the mass defect alone in mega-electron-volts
B$931.5$ MeV, the conversion factor of one atomic mass unit
C$0.5$ u, ignoring the conversion to energy entirely here
D$465.8$ MeV, since $\Delta m c^2 = 0.5\cdot 931.5$ MeV
Answer & Solution
Correct answer: D. $465.8$ MeV, since $\Delta m c^2 = 0.5\cdot 931.5$ MeV
Binding energy $= \Delta m c^2 = 0.5\cdot 931.5 \approx 466$ MeV.
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