In a dihybrid cross TtRr × TtRr in pea, the **probability** of produci…

Question

In a dihybrid cross TtRr × TtRr in pea, the **probability** of producing a homozygous recessive (ttrr) offspring is:

Accepted Answer

C. 1/16

Tt × Tt yields tt with probability 1/4. Independently, Rr × Rr yields rr with probability 1/4. By independent assortment, P(ttrr) = (1/4)(1/4) = 1/16 — which matches the single '1' in the 9:3:3:1 ratio.

Answer

1/4

Answer

1/8

Answer

9/16

In a dihybrid cross TtRr × TtRr in pea, the probability of producing a homozygous recessive (ttrr) offspring is:

Keep practising Unit 5C: Non-Mendelian Genetics & Population Transmission