Which half-reaction from the given notes represents oxidation?

Question

Accepted Answer

C. $Zn \rightarrow Zn^{2+} + 2e^{-}$

In oxidation, electrons appear on the product side because the species loses electrons. In $Zn \rightarrow Zn^{2+} + 2e^{-}$, zinc loses two electrons, so this is oxidation. Option A is reduction because copper ions gain electrons.

Answer

$Cu^{2+} + 2e^{-} \rightarrow Cu$

Answer

$Zn^{2+} + 2e^{-} \rightarrow Zn$

Answer

$SO_4^{2-} \rightarrow SO_2 + 2e^{-}$