The middle term of (a + b)^8 is
A⁸C_4 a⁵ b³
B⁸C_3 a⁵ b³
C⁸C_4 a⁴ b⁴
D⁸C_5 a³ b⁵
Answer & Solution
Correct answer: C. ⁸C_4 a⁴ b⁴
For even n = 8 the single middle term is T_(n/2 + 1) = T_5 = ⁸C_4 a^(8−4) b^4 = ⁸C_4 a⁴ b⁴.
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