The middle term of (a + b)^8 is
A⁸C_4 a⁵ b³
B⁸C_3 a⁵ b³
C⁸C_4 a⁴ b⁴
D⁸C_5 a³ b⁵
Answer & Solution
Correct answer: C. ⁸C_4 a⁴ b⁴
For even n = 8 the single middle term is T_(n/2 + 1) = T_5 = ⁸C_4 a^(8−4) b^4 = ⁸C_4 a⁴ b⁴.
Keep practising Binomial Theorem
Browse all Binomial Theorem questions for GRE, or explore more Mathematics topics.
Related questions
GMAT · Quantitativeaptitude · Coordinate Geometry — Memory FlipThe general term in the expansion of $(x + 2)^{10}$ is:The expansion of $(a + b)^n$ contains how many terms?The sum of coefficients of ODD powers of x in (1 + x)^10 equals(1.01)^5 evaluated using the binomial expansion to first two terms only is approximatelyExpanding (2x + 3y)^5 using Pascal's row 1 5 10 10 5 1, the coefficient of x²y³ isThe coefficient of x^5 in (1 + x)^8 isThe term independent of x in the expansion of (x + 1/x)^6 is