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If a point on the line $\dfrac{x-x_1}{a}=\dfrac{y-y_1}{b}=\dfrac{z-z_1}{c}=\lambda$, then its coordinates are
A$(x_1+a,\; y_1+b,\; z_1+c)$
B$(x_1+a\lambda,\; y_1+b\lambda,\; z_1+c\lambda)$
C$(a\lambda,\; b\lambda,\; c\lambda)$
D$(x_1+\lambda,\; y_1+\lambda,\; z_1+\lambda)$
Answer & Solution
Correct answer: B. $(x_1+a\lambda,\; y_1+b\lambda,\; z_1+c\lambda)$
From $\dfrac{x-x_1}{a}=\dfrac{y-y_1}{b}=\dfrac{z-z_1}{c}=\lambda$, we get $x-x_1=a\lambda$, $y-y_1=b\lambda$, and $z-z_1=c\lambda$. Hence the point is $(x_1+a\lambda,\; y_1+b\lambda,\; z_1+c\lambda)$.
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