If a point on the line $\dfrac{x-x_1}{a}=\dfrac{y-y_1}{b}=\dfrac{z-z_1…

Question

If a point on the line $\dfrac{x-x_1}{a}=\dfrac{y-y_1}{b}=\dfrac{z-z_1}{c}=\lambda$, then its coordinates are

Accepted Answer

B. $(x_1+a\lambda,\; y_1+b\lambda,\; z_1+c\lambda)$

From $\dfrac{x-x_1}{a}=\dfrac{y-y_1}{b}=\dfrac{z-z_1}{c}=\lambda$, we get $x-x_1=a\lambda$, $y-y_1=b\lambda$, and $z-z_1=c\lambda$. Hence the point is $(x_1+a\lambda,\; y_1+b\lambda,\; z_1+c\lambda)$.

Answer

$(x_1+a,\; y_1+b,\; z_1+c)$

Answer

$(a\lambda,\; b\lambda,\; c\lambda)$

Answer

$(x_1+\lambda,\; y_1+\lambda,\; z_1+\lambda)$