Practice free →
HomeJEE Main › Vectors & 3D Geometry › A student claims that the perpendicular distance…

A student claims that the perpendicular distance from a point to a line equals the magnitude of the projection of the joining vector onto the line's direction vector. Why is this incorrect?

ABecause perpendicular distance is the component parallel to the line
BBecause projection on the line gives the parallel component, whereas perpendicular distance comes from the component orthogonal to the line
CBecause distance to a line is always zero for any point
DBecause projection can only be used in two dimensions, not three
Answer & Solution
Correct answer: B. Because projection on the line gives the parallel component, whereas perpendicular distance comes from the component orthogonal to the line
Underlying idea: split the vector from a point on the line to the given point into parallel and perpendicular components relative to the line. 1. Let $\vec v$ be the vector from a point on the line to the external point, and let $\vec u$ be a direction vector of the line. 2. The projection of $\vec v$ onto $\vec u$ measures the part of $\vec v$ along the line, not away from it. 3. The shortest distance to the line is the length of the component of $\vec v$ perpendicular to $\vec u$. 4. Hence the correct distance is obtained by removing the parallel component from $\vec v$, giving $$ \text{distance}=\sqrt{|\vec v|^2-\frac{(\vec v\cdot\vec u)^2}{|\vec u|^2}}. $$ Option A reverses the roles of the components. Option C is false except when the point lies on the line. Option D is false because vector projection works in any dimension.
Solve this in the app — JEE Main practice & 24k+ MCQs →
Related questions