allery$\displaystyle\int \sec^2 x\,dx$ equals:
A$\cot x + C$
B$\tan x + C$
C$\sec x + C$
D$-\tan x + C$
Answer & Solution
Correct answer: B. $\tan x + C$
$\dfrac{d}{dx}(\tan x) = \sec^2 x$, hence $\int \sec^2 x\,dx = \tan x + C$.
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