Home › CBSE Class 12 › Alkenes › The Rydberg formula for the wavelength of radiat…
The Rydberg formula for the wavelength of radiation emitted when an electron in a hydrogen atom jumps from level $n_2$ to level $n_1$ (with $n_2 > n_1$) is:
A$\lambda = R\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$
B$\dfrac{1}{\lambda} = R\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$
C$\dfrac{1}{\lambda} = R\left(\dfrac{1}{n_2^2} - \dfrac{1}{n_1^2}\right)$
D$\dfrac{1}{\lambda} = R\left(\dfrac{1}{n_1} - \dfrac{1}{n_2}\right)$
Answer & Solution
Correct answer: B. $\dfrac{1}{\lambda} = R\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$
The standard Rydberg form for hydrogen is $\dfrac{1}{\lambda} = R\left(\dfrac{1}{n_1^2} - \dfrac{1}{n_2^2}\right)$ with $n_2 > n_1$, where $R = 1.097 \times 10^7\,\text{m}^{-1}$. Since $n_2 > n_1$ this expression is positive, giving a real wavelength. The form in option A would yield a negative right-hand side and is therefore wrong.
Related questions
Besides VSEPR and the Kossel Lewis approach, which two theories are listed?Which theory is abbreviated VSEPR?Why can lattice enthalpy not be calculated directly from attraction and repulsion alone?Ionic bonds form most easily between elements with low ionization enthalpies and high negaWhat is the lattice enthalpy of sodium chloride?Lattice enthalpy is the energy required to separate one mole of an ionic solid into:The structures contributing to a resonance hybrid are called:Why was the concept of resonance introduced?