In a Young's double slit experiment, the slits are separated by $d = 0…

Question

In a Young's double slit experiment, the slits are separated by $d = 0.5\,	ext{mm}$ and the screen is $D = 1.0\,	ext{m}$ away. With light of wavelength $600\,	ext{nm}$, the fringe width on the screen is:

Accepted Answer

C. $1.2\,	ext{mm}$

Fringe width $\beta = \dfrac{\lambda D}{d} = \dfrac{600 	imes 10^{-9} 	imes 1.0}{0.5 	imes 10^{-3}} = 1.2 	imes 10^{-3}\,	ext{m} = 1.2\,	ext{mm}$.

Answer

$0.3\,	ext{mm}$

Answer

$0.6\,	ext{mm}$

Answer

$3.0\,	ext{mm}$

In a Young's double slit experiment, the slits are separated by $d = 0.5\,\text{mm}$ and the screen is $D = 1.0\,\text{m}$ away. With light of wavelength $600\,\text{nm}$, the fringe width on the screen is: