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The coordinates of the point dividing the line joining $(x_1,y_1)$ and $(x_2,y_2)$ internally in the ratio m:n are:
A$\left(\dfrac{mx_1+nx_2}{m+n},\ \dfrac{my_1+ny_2}{m+n}\right)$
B$\left(\dfrac{mx_2+nx_1}{m+n},\ \dfrac{my_2+ny_1}{m+n}\right)$
C$\left(\dfrac{x_1+x_2}{m+n},\ \dfrac{y_1+y_2}{m+n}\right)$
D$\left(\dfrac{mx_2-nx_1}{m-n},\ \dfrac{my_2-ny_1}{m-n}\right)$
Answer & Solution
Correct answer: B. $\left(\dfrac{mx_2+nx_1}{m+n},\ \dfrac{my_2+ny_1}{m+n}\right)$
Section formula (internal, ratio m:n): ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
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