alleryThe sum of the first n positive integers is given by:
A$\dfrac{n(n+1)}{2}$
B$\dfrac{n^2}{2}$
C$n(n+1)$
D$\dfrac{n(n-1)}{2}$
Answer & Solution
Correct answer: A. $\dfrac{n(n+1)}{2}$
Sum of first n integers = n(n+1)/2.
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