$\displaystyle\int \frac{1}{x}\,dx$ equals:
A$x\ln x + C$
B$\dfrac{1}{x^2}+C$
C$\ln|x| + C$
D$-\dfrac{1}{x^2} + C$
Answer & Solution
Correct answer: C. $\ln|x| + C$
∫(1/x) dx = ln|x| + C.
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