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The rate of change of the volume of a sphere $V = \tfrac{4}{3}\pi r^3$ with respect to its radius $r$ is:
A$\tfrac43\pi r^2$
B$3\pi r^2$
C$4\pi r^2$
D$\pi r^2$
Answer & Solution
Correct answer: C. $4\pi r^2$
dV/dr = d/dr(4/3·πr³) = 4πr².
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