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If $I_1=2\text{ A}$, $I_2=3\text{ A}$, $I_3=5\text{ A}$, $I_4=4\text{ A}$, and $I_5=1\text{ A}$ for the node in the figure, what is $I_6$? ![](https://qallery.app/diagrams/v2_74feee0d9633/img-000.jpeg)

A$3\text{ A}$
B$5\text{ A}$
C$7\text{ A}$
D$9\text{ A}$
Answer & Solution
Correct answer: B. $5\text{ A}$
By Kirchhoff's Current Law, $I_1+I_2+I_3=I_4+I_5+I_6$. Substituting gives $2+3+5=4+1+I_6$, so $10=5+I_6$, hence $I_6=5\text{ A}$.
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