For any two events A and B, $P(A\cup B)$ equals:
A$P(A)P(B)$
B$P(A)-P(B)$
C$P(A)+P(B)-P(A\cap B)$
D$P(A)+P(B)$
Answer & Solution
Correct answer: C. $P(A)+P(B)-P(A\cap B)$
Addition theorem: P(A∪B) = P(A) + P(B) − P(A∩B).
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