Home › JEE Main › Mathematics › Conic Sections — Parabola ›  For the parabola $y^2 = 4ax$ ($a > 0$), the focus and the directrix are located at:
AFocus $(a, 0)$; directrix $x = -a$
BFocus $(-a, 0)$; directrix $x = a$
CFocus $(0, a)$; directrix $y = -a$
DFocus $(0, 0)$; directrix $x = 0$
Answer & Solution
Correct answer: A. Focus $(a, 0)$; directrix $x = -a$
Definition: a parabola is the locus of points equidistant from a fixed point (**focus**) and a fixed line (**directrix**).
For $y^2 = 4ax$:
- Focus at $(a, 0)$ — on the positive $x$-axis at distance $a$ from the vertex.
- Directrix $x = -a$ — the vertical line on the *opposite* side of the vertex, also distance $a$ away.
This symmetry around the vertex is the load-bearing intuition.
Related questions
For the parabola $y^2 = 16x$, find the equation of the directrix.A parabola has its vertex at the origin, its axis along the positive $x$-axis, and passes Find the equation of the parabola with vertex at the origin and focus at $(0, -3)$.Find the length of the latus rectum of the parabola $y^2 = 8x$.
The figure shows a parab