Home › JEE Main › Mathematics › Conic Sections — Ellipse ›  From the figure, the vertices of the horizontal ellipse $\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1$ are at:
A$(\pm a, 0)$
B$(0, \pm b)$
C$(\pm c, 0)$
D$(a, b)$
Answer & Solution
Correct answer: A. $(\pm a, 0)$
The vertices are the endpoints of the **major axis**. For a horizontal ellipse, the major axis is along the $x$-axis with length $2a$, so vertices sit at $(\pm a, 0)$.
Option B gives the endpoints of the *minor* axis. Option C marks the **foci**, not vertices.
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