The probability that a marksman will hit a target is given as $\frac{1}{5}$. Then the probability that at least once hit in 10 shots is

Let the probability of a hit in one shot be $p=\frac{1}{5}$. Then the probability of a miss in one shot is $1-p=\frac{4}{5}$.<br><br>The probability of missing all $10$ shots is $$\left(\frac{4}{5}\right)^{10}.$$ Therefore, the probability of getting at least one hit in $10$ shots is $$1-\left(\frac{4}{5}\right)^{10}.$$ This matches option $A$.