According to the Bohr model, the ground-state energy of a hydrogen atom is:
A$-13.6$ eV
B$-6.8$ eV
C$-27.2$ eV
D$-3.4$ eV
Answer & Solution
Correct answer: A. $-13.6$ eV
Bohr's energy formula: $E_n = -\dfrac{13.6}{n^2}$ eV for hydrogen.
For the ground state $n = 1$: $E_1 = -13.6$ eV.
- Option A ($-3.4$ eV) is $E_2$.
- Option D ($-27.2$ eV) is the magnitude of *twice* the ground-state energy (a common confusion with the virial-theorem relation $E = -\frac{1}{2}|U|$).
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