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The product of any three consecutive positive integers is always divisible by
A4
B12
C9
D6
Answer & Solution
Correct answer: D. 6
Among any three consecutive integers, at least one is divisible by 2 and exactly one is divisible by 3. Hence the product is divisible by $2 \times 3 = 6$. It need not be divisible by 4 (e.g. $1\cdot2\cdot3 = 6$).
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