The de Broglie wavelength of an electron in the $n$th Bohr orbit, in t…

Question

The de Broglie wavelength of an electron in the $n$th Bohr orbit, in terms of the orbit radius $r_n$, is

Accepted Answer

C. $\lambda = 2\pi r_n/n$

Bohr's quantisation $2\pi r_n = n\lambda$ is exactly de Broglie's standing-wave condition — an integer number of wavelengths fit around the circumference.
**Solving:** $\lambda = 2\pi r_n/n$.

Answer

$\lambda = n r_n$

Answer

$\lambda = 2\pi n r_n$

Answer

$\lambda = r_n/n$

The de Broglie wavelength of an electron in the $n$th Bohr orbit, in terms of the orbit radius $r_n$, is

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